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6w^2=w+6
We move all terms to the left:
6w^2-(w+6)=0
We get rid of parentheses
6w^2-w-6=0
We add all the numbers together, and all the variables
6w^2-1w-6=0
a = 6; b = -1; c = -6;
Δ = b2-4ac
Δ = -12-4·6·(-6)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{145}}{2*6}=\frac{1-\sqrt{145}}{12} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{145}}{2*6}=\frac{1+\sqrt{145}}{12} $
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